swapping of two numbers in C++

 #include <iostream>

using namespace std;

int main()

{

int a,b,c;

cout<<"enter value for a";

cin>>a;

cout<<"enter value for b";

cin>>b;

c=a;

a=b;

b=c;

cout<<"after swapping\n";

cout<<"a="<<a<<"b="<<b;

return 0;

}

Output:

enter value for a 12

enter value for b 22

after swapping

a=22 b=12

swapping of two numbers by reference

#include<iostream>

using namespace std;

void swap(int &x, int &y)

{

int temp;

temp=x;

x=y;

y=temp;

return ;

}

int main()

{

int a,b;

cout<<"before swapping ";

cout<<"value for a is ";

cin>>a;

cout<<"value of b is ";

cin>>b;

swap(a,b);

cout<<" after swapping ";

cout<<"\nthe value of a : "<<a;

cout<<"\nvalue of b is "<<b;

return 0;

}

output:

before swapping value for a is 12

value of b is 22

 after swapping

the value of a : 22

value of b is 12

Swapping of two numbers using pointers and functions:

#include<iostream>

using namespace std;

int swap(int*,int*);

int main()

{

int a,b;

cout<<"enter value for a: ";

cin>>a;

cout<<"enter value for b: ";

cin>>b;

swap(&a,&b);

cout<<"value fo a is: "<<a;

cout<<"\nvalue for b is: "<<b;

}

int swap(int *x,int *y)

{

int t;

t=*x;

*x=*y;

*y=t;

}

output:

enter value for a: 12

enter value for b: 22

value fo a is: 22

value for b is: 12